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The vapour pressure of an aqueous soluti...

The vapour pressure of an aqueous solution of glucose is `750 mm` of `Hg` at `373 K`. Calculate molality and mole fraction of solute.

A

(a) `(1)/(10)`

B

(b) `(1)/(7.6)`

C

( c) `(1)/(35)`

D

(d) `(1)/(76)`

Text Solution

Verified by Experts

The correct Answer is:
D
`(P^(@)-P_(S))/(P^(@)) = (n)/(n+N)`
(at `373K V.P.` of `H_(2)O = 760 mm Hg`)
`(n)/(n+N) = (760-750)/(760) = (1)/(76)`
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