Home
Class 12
CHEMISTRY
The freezing point of a 0.05 molal solut...

The freezing point of a `0.05` molal solution of a non-electrolyte in water is:
(`K_(f) = 1.86 "molality"^(-1)`)

A

(a) `-1.86^(@)C`

B

(b) `-0.93^(@)C`

C

(c ) `-0.093^(@)C`

D

(d) `0.093^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
C
`Delta T_(f) = 1.86 xx 0.05 = 0.093`,
`:. T_(f) = 0-0.093 = -0.093^(@)C`
Promotional Banner

Topper's Solved these Questions

  • DILUTE SOLUTION AND COLLIGATIVE PROPERTIES

    P BAHADUR|Exercise Exercise 3B Objectice Problems|1 Videos

  • DILUTE SOLUTION AND COLLIGATIVE PROPERTIES

    P BAHADUR|Exercise Exercise 9 Advanced Numerical|12 Videos

  • CHEMICAL KINETICS

    P BAHADUR|Exercise Exercise 9|13 Videos

  • ELECTROCHEMISTRY

    P BAHADUR|Exercise Exercise (9) ADVANCED NUMERICAL PROBLEMS|36 Videos

Similar Questions

Explore conceptually related problems

The freezing point of a 0.05 molal solution of a non-electrolyte in water is [K_(f)=1.86K//m]

The molal depression constant for water is 1.86^(@)C . The freezing point of a 0.05-molal solution of a non-electrolyte in water is

KBr is 80% ionized in solution. The freezing point of 0.4 molal solution of KBr is : K_f (H_2O) = 1.86 (K kg)/("mole")

What is the depression in freezing point of a solution of non-electrolyte if elevation in boiling point is 0.13K ? (k_(b)=0.52 mol^(-1) kg, k_(f)= 1.86 mol^(-1) kg)

What will be the freezing point of a 0.5 m KCl solution ? The molal freezing point constant of water is 1.86^@C m^(-1) .