Osmotic pressure of `40%` (wt.`//`vol.) urea solution is `1.64 atm` and that of `3.42%` (wt.`//`vol.) cane sugar is `2.46 atm`. When equal volumes of the above two solutions are mixed, the osmotic pressure of the resulting solution is:

Options

A. (a) `1.64 atm`
B. (b) `2.46 atm`
C. ( c) `4.10 atm`
D. (d) `2.05 atm`

Answer

D

Explanation

`pi = (pi_(1)+pi_(2))/(2)`, if equal volume are mixed, volume of solution become double.