The values of observed and calculated molecular wrights of silver nitrate are `92.64` and `170` respectively.The degree of dissociation of silver nitrate is:

Options

A. (a) `60%`
B. (b) `83.5%`
C. (c ) `46.7%`
D. (d) `60.23%`

Answer

B

Explanation

`i` for `AgNO_(3) = ("normal mole wt.")/("observed mol. Wt.") = 1+alpha`
`:. alpha = i- 1 = (170)/(92.64) - 1 = 0.835 = 83.5%`