Home
Class 12
CHEMISTRY
Calculate the amount of ice that will se...

Calculate the amount of ice that will separate out on cooling containing `50 g `of ethylene glycol in `200 g` of water to `-9.3^(@)C (K_(f)` for water =`1.86 K mol^(-1) kg`)

A

(a) `38.71 g`

B

(b) `38.71 mg`

C

(c ) `42 g`

D

(d) `42 mg`

Text Solution

Verified by Experts

The correct Answer is:
A

`:. Delta T = (1000 xx K_(f) xx w)/(m xx W)`
`9.3 = (1000 xx 1.86 xx 50)/(62 xx W)`
`:. W = 161.29`
`:.` Ice separated `= 200-161.29 = 38.71 g`
Promotional Banner

Topper's Solved these Questions

  • DILUTE SOLUTION AND COLLIGATIVE PROPERTIES

    P BAHADUR|Exercise Exercise 3B Objectice Problems|1 Videos
  • DILUTE SOLUTION AND COLLIGATIVE PROPERTIES

    P BAHADUR|Exercise Exercise 9 Advanced Numerical|12 Videos
  • CHEMICAL KINETICS

    P BAHADUR|Exercise Exercise 9|13 Videos
  • ELECTROCHEMISTRY

    P BAHADUR|Exercise Exercise (9) ADVANCED NUMERICAL PROBLEMS|36 Videos

Similar Questions

Explore conceptually related problems

Calculate the amount of ice that will separate out on cooling a solution containing 50g of ethylene glycol in 200g water to -9.3^(@)C ( K_(f) for water = 1.86 "K kg mol"^(-1) )

The amount of ice that will separate out on cooling a solution containing 50 g ethylene glycol in 200 g water to -9.3^(@)C is : ( K'_(f) = 1.86 K "molality"^(-1) )

What will be the amount of ice separated on cooling solution of 40g ethylene glycol in 400 g water upto -9.3^(@) C ?

The amount of ice that will separate out from a solution containing 25 g of ethylene glycol in 100 g of water that is cooled to -10^(@)C , will be [Given : K_(f) "for" H_(2)O = 1.86K mol^(-1) kg ]

A solution containing 62 g ethylene glycol in 250 g water is cooled to -10^(@)C . If K_(f) for water is 1.86 K mol^(-1) , the amount of water (in g) separated as ice is :