Home
Class 12
CHEMISTRY
A substance (A) is completely trimerised...

A substance `(A)` is completely trimerised on dissolution in solvent `B`. The van't Hoff factor `(i)` for such change is:

A

(a) `1`

B

(b) `2`

C

(c ) `3`

D

(d) `1//3`

Text Solution

Verified by Experts

The correct Answer is:
D
`3A rarr A_(3)`,
van't Hoff factor (i) `= 1- alpha + (alpha)/(n)`
where `alpha` is degree of assciation (here `alpha = 1`) and `n` is no. of molecules undergoing association (here `n = 3`).
Promotional Banner

Topper's Solved these Questions

  • DILUTE SOLUTION AND COLLIGATIVE PROPERTIES

    P BAHADUR|Exercise Exercise 3B Objectice Problems|1 Videos

  • DILUTE SOLUTION AND COLLIGATIVE PROPERTIES

    P BAHADUR|Exercise Exercise 9 Advanced Numerical|12 Videos

  • CHEMICAL KINETICS

    P BAHADUR|Exercise Exercise 9|13 Videos

  • ELECTROCHEMISTRY

    P BAHADUR|Exercise Exercise (9) ADVANCED NUMERICAL PROBLEMS|36 Videos

Similar Questions

Explore conceptually related problems

Vant Hoff factor (i)-

, van't -Hoff factor (i) for this reaction is:

Van't Hoff factor is _____.

What is Van't Hoff factor ?

If van't Hoff factor i=1,then

For a solute undergoing association in a solvent, the van't hoff factor

The Van't Hoff factor (i) for K_(2)SO_(4) is ………. .

What is the Van't Hoff factor for sodium phosphate ?