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The freezing point of aqueous solution t...

The freezing point of aqueous solution that contains `5%` by mass urea. `1.0%` by mass `KCl` and `10%` by mass of glucose is:
`(K_(f) H_(2)O = 1.86 K "molality"^(-1))`

A

(a) `290.2 K`

B

(b) `285.5 K`

C

( c) `269.93 K`

D

(d) `250 K`

Text Solution

Verified by Experts

The correct Answer is:
C
` Delta T = Delta T` for glucose `+ Delta T` for `KCl+Delta T` for urea
`= (1000 xx 1.86 xx 10)/(100 xx 180) + (1000 xx 1.86 xx 1 xx 2)/(74.5 xx 100) + (1000 xx 1.86 xx 5)/(100 xx 60) = 3.069`
`:. f.pt = 273 - 3.069 = 269.93 K`
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