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The vapour pressure of water at room tem...

The vapour pressure of water at room temperature is lowered by `5%` by dissolving a solute in it. What is approximate molality of solution:

A

(a) `2`

B

(b) `1`

C

(c ) `4`

D

(d) `3`

Text Solution

Verified by Experts

The correct Answer is:
D
`(P^(@)-P_(S))/(P_(S)) = (n)/(N) = (n xx M)/(W) = (n xx M xx 1000)/(W xx 1000)`
`= ("molality" xx M)/(1000)`
Thus `(100-95)/(95) = (m xx 18)/(1000)`
`:. m = 2.92`
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