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Equal amounts of a solute are dissolved ...

Equal amounts of a solute are dissolved in equal amounts of two solvents `A` and `B`. The lowering of vapour pressure of solution `A` has twice the lowering of vapour pressure for solution `B`. If `Mw_(A)` and `Mw_(B)` are the molecular weights of solvents `A` and `B`, respectively , then
a.`Mw_(A) = Mw_(B)` , b. `Mw_(A) = Mw_(B)//2`,
c.`Mw_(A) = 4Mw_(B)`, d. `Mw_(A) = 2Mw_(B)`

A

(a) `M_(A) = M_(B)`

B

(b) `M_(A) = M_(B)//2`

C

( c) `M_(A) = 4M_(B)`

D

(d) `M_(A) = 2M_(B)`

Text Solution

Verified by Experts

The correct Answer is:
D
` [(P^(@)-P_(S))/(P^(@))]=(n)/(N_(A))` and `[(P^(@)-P_(S))/P^(@)]_(B)=(n)/(N_(B))`
`:. ([[P^(@)-P_(S))/(P^(@))]_(A))/([[P^(@)-P_(S))/(P^(@))]_(B))=(N_(B))/(N_(A))=(W_(B))/(M_(B))xx(M_(A))/(W_(A))`
`2=(M_(A))/(M_(B)) ( :. W_(A)=W_(B))`
`:. M_(A)=2M_(B)`
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