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At higher altitude, boiling of water is ...

At higher altitude, boiling of water is `95^(@)C`. The amount of `NaCl` added to `1 kg` water `(k_(b)=0.52 K mol^(-1)kg)` in order to raise the b.pt. of solution to `100 ^(@)C` is (assume `90%` ionisation of `NaCl`):

A

`296.5 g`

B

`281.25 g`

C

`270 g`

D

`310 g`

Text Solution

Verified by Experts

The correct Answer is:
A
`Delta T = (1000 xx K_(b) xx w)/(m xx W)(1+alpha)`
`5 = (1000 xx 0.52 xx w)/(58.5 xx 1000) xx (1.90)` , `(because alpha = 0.9)`
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