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The elevation in boiling point of a solu...

The elevation in boiling point of a solution `dT_(b)` is related with molality of solution `(m)` by the reaction:
`dT_(b)=[(RT_(b)^(2))/(DeltaH_(vap))][(M_(1))/(1+mM_(1))]`, where `M_(1)` is moalr mass of solvent and `DeltaH_(vap)` is heat of vaporisation of solvent. For a dilute solution, the relation `((delT_(b))/(delT_(n)))_(mto0)`
gives:

A

Molal ebullioscopic constant

B

Elevation in boiling point

C

Elevation in boiling `delT_(b)` becomes more predominant

D

Boiling point of solvent

Text Solution

Verified by Experts

The correct Answer is:
A
`((delT_(b))/(delm))_(m rarr0) = (RT_(b)^(2)M_(1))/(Delta H_(vap.)) = K_(b)`
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