Home
Class 12
CHEMISTRY
30 mL of 0.1M KI(aq.) and 10 mL of 0.2M ...

`30 mL` of `0.1M KI_(aq.)` and `10 mL` of `0.2M AgNO_(3)` are mixed. The solution is then filtered out. Assuming that no change in total volume, the resulting solution will freezing at:
`[K_(f) "for" H_(2)O = 1.86K kg mol^(-1)`, assume molality = molality]

A

(a) `0.22`

B

(b) `0.28`

C

( c) `0.149`

D

(d) `0.074`

Text Solution

Verified by Experts

The correct Answer is:
B

`{:(,KI,+,AgNO_(3),rarr,KNO_(3)+,AgI),("milli-mole",30xx0.1,,10xx0.2,,,),(,=3,,=2,,0,0),("milli-mole left",1,,0,,2,2):}`
`:. [KI]` in solution `= (1)/(40)` and `[KNO_(3)]`
`= (2)/(40)`
`"molarity = molality"`
`:. Delta T_(f) = Delta T_(f) ("by" KI) + Delta T_(f) ("by" KNO_(3))`
`= "molality" xx 1.86 xx (1+alpha_(1)) + "molality" xx 1.86 xx (1+alpha_(2))`
`= (1)/(40) xx 1.86 xx 2+(2)/(40) xx 1.86 xx 2`
`= 0.093 + 0.186 = 0.279 ~~ 0.28`
Promotional Banner

Topper's Solved these Questions

  • DILUTE SOLUTION AND COLLIGATIVE PROPERTIES

    P BAHADUR|Exercise Exercise 3B Objectice Problems|1 Videos
  • DILUTE SOLUTION AND COLLIGATIVE PROPERTIES

    P BAHADUR|Exercise Exercise 9 Advanced Numerical|12 Videos
  • CHEMICAL KINETICS

    P BAHADUR|Exercise Exercise 9|13 Videos
  • ELECTROCHEMISTRY

    P BAHADUR|Exercise Exercise (9) ADVANCED NUMERICAL PROBLEMS|36 Videos

Similar Questions

Explore conceptually related problems

Equal volume of 1.0 M KCl and 1.0 M AgNO_(3) are mixed . The depression of freezing point of the resulting solution will be : ( K_(f) (H_(2)O) = 1.86K kg mol^(-1) , Assume : 1M = 1m)

0.1 M KI and 0.2 M AgNO_(3) are mixed in 3 : 1 volume ratio. The depression of freezing point of the resulting solution will be [ K_(b)(H_(2)O) = 1.86 K kg "mol"^(-1) ]:

Calculate the molecular weight of a substance whose 7.0% (by weight) solution in water freezes at -0.89^(@)C . (k_(f) "for" H_(2)O=1.86K"molality"^(-1) ).

In a 0.5 molal solution KCl, KCl is 50% dissociated. The freezing point of solution will be ( K_(f) = 1.86 K kg mol^(-1) ):

In a 2.0 molal aqueus solution of a weak acid HX the degree of disssociation is 0.25. The freezing point of the solution will be nearest to: ( K_(f)=1.86 K kg "mol"^(-1) )

10mL of 0.5NHCl, 30mL of 0.1NHNO_(3) and 75mL of 0.1M H_(2)SO_(4) are mixed together. The normality of the resulting solution will be :

Calculate depression of freezing point for 0.56 molal aq. Solution of KCl. (Given : K_f(H_(2)O) = 1.8 kg mol^(-1) ).