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18g of glucose (C(6)H(12)O(6))is added t...

`18`g of glucose `(C_(6)H_(12)O_(6))`is added to `178.2` g of water. The vapour pressure of water for this aqueous solution at `100^@C`is :

A

`759` torr

B

`7.60` torr

C

`76.0` torr

D

`752.40` torr

Text Solution

Verified by Experts

The correct Answer is:
D
`(P^(@)-P_(S))/(P_(S)) = (n)/(N) = (18 xx 18)/(180 xx 178.2) = 0.01`
`:. (760-P_(S))/(P_(S)) = 0.01`
(`because P^(@) = 760` torr at `b.pt. "of" H_(2)O`)
`P_(S) = 752.47 "torr"`
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