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At 80^@C, the vapour pressure of pure li...

At `80^@C`, the vapour pressure of pure liquid `A` is `520 mm` Hg and that of pure liquid `B` is `1000 mm Hg`. If a mixture of solution `A` and `B` boils at `80@C` and `1 atm` pressure, the amount of `A` in the mixture is `(1 atm =760 mm Hg)`
a. `50 mol %` , b.`52 mol %` ,c.`34 mol%` ,d.`48 mol %`

A

`52` mol per cent

B

`34` mol per cent

C

`48` mol per cent

D

`50` mol per cent

Text Solution

Verified by Experts

The correct Answer is:
D
`P_(m) = P_(A)^(@)X_(A) + P_(B)^(@)X_(B)`
`760 = 520 X_(A) + P_(B)^(@)(1-X_(A))`
`:. X_(A) = 0.5 = 50%`
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