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0.002m aqueous solution of an ionic comp...

`0.002m` aqueous solution of an ionic compound `Co(NH_(3))_(5)(NO_(2))CI` freezes at `-0.00732^(@)C`.Number of moles of ions which 1 mole of ionic compound produces in water will be `(K_(f) = 1.86^(@)C//m)`

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The correct Answer is:
2
The number of moles of ions produced by `1` mole of ionic compound `= i`
`Delta T_(f) = K_(f) xx "malality" xx i`
`:. i = (Delta T_(f))/(K_(f) xx "molality") = (0.00732)/(1.86 xx 0.002)`
`= 1.97 ~~2`
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