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A mixture of two immiscible liquids nitr...

A mixture of two immiscible liquids nitrobenzene and water at `99^(@)C` has a partial vapour pressure of water `733 mm` and that of nitrobenzene `27 mm`. Calculate the ratio of the weights of nitrobenzene to the water in the distillate.

Text Solution

Verified by Experts

The correct Answer is:
4
`P_(M) = P_(H_(2)O) + P_(NB) = 733+27=760 mm`
If `X_(A)` is mole fraction in gaseous phase ltbgt `P' = P_(M).X_(A)`
`:. 27 = 760 xx (((w_(2))/(123))/((w_(1))/(18)+(w_(2))/(123)))` for water
`:. (w_(1))/(w_(2)) = 4`
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