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0.75 g of a non-electrolyte was dissolve...

`0.75 g` of a non-electrolyte was dissolved in `87.9 g` of benzene. This raised the boiling point of benzene by `0.25^(@)C`. If the molecular mass of non-electrolyte is `103`, calculate the molal elevation constant for bezene.

Text Solution

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The correct Answer is:
3
`K_(b) = (Delta T_(b) xx m xx W)/(w xx 1000)`
Given, `Delta T_(b) = 0.25 K, m = 103, w= 0.75g`,
`W = 87.9g`
`:. K_(b) = (0.25 xx 103 xx 87.9)/(0.75 xx 1000) ~~ 3.0 K log mol^(-1)`
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