Mole fraction of a solute (in a solvent of mol.wt.`250`) is `0.02`. If elevation constant of solvent is `24.5 K molality^(-1)` , find the elevation in boiling point.

Answer

2

Explanation

`(n)/(n+N) = 0.02`
`(N)/(n+N) = 0.98`
`(n)/(N) = (1)/(49)`
`(w xx M xx 1000)/(m xx W xx 1000) = (1)/(49)`
Molality `= (1)/(49) xx (1000)/(M)`
`Delta T_(b) =K'_(b) xx "molality"`
`Delta T_(b) = (1000 xx 24.5)/(49 xx 250) = 2`