Home
Class 12
CHEMISTRY
Calculate osmotic pressure of a solution...

Calculate osmotic pressure of a solution obtained by mixing `100 mL` of `3.4%` solution "(weight/volume)" of urea "(molecular weight 60)" and `100 mL` of `1.6%` solution "(weight/volume)" of cane sugar "(molecular weight 342)" at `20^(@)C`.

Text Solution

Verified by Experts

The correct Answer is:
`7.38 atm`;
Promotional Banner

Topper's Solved these Questions

  • DILUTE SOLUTION AND COLLIGATIVE PROPERTIES

    P BAHADUR|Exercise Exercise 3B Objectice Problems|1 Videos

  • DILUTE SOLUTION AND COLLIGATIVE PROPERTIES

    P BAHADUR|Exercise Exercise 9 Advanced Numerical|12 Videos

  • CHEMICAL KINETICS

    P BAHADUR|Exercise Exercise 9|13 Videos

  • ELECTROCHEMISTRY

    P BAHADUR|Exercise Exercise (9) ADVANCED NUMERICAL PROBLEMS|36 Videos

Similar Questions

Explore conceptually related problems

The osmotic pressure of a solution containing 100 ml of 3.4% solution (w/v) of urea (mol mass 60 g/mole) and 50 ml of 1.6% solution (w/v) of cane-sugar (mol mass 342 g/mole) at 27ºC is:

Calculte the osmotic pressure os a solution obtained by mixing 100 mL of 4.5% solution of urea (mol. Mass =60) and 100 mL pf 3.42% solution of cane sugar (mol. Mass =342) at 300 K. (Given R=0.0821 L atm K^(-1) mol^(-1))

Osmotic pressure of a solution obtained by mixing 100 mL of 1.4% solution of urea (mol mass = 60) and 100 mL of 3.42% of cane sugar solution (mol mass = 342) at 20^(@)C (R = 0.0821 L atm K^(-1) mol^(-1))

Calculate the osmotic pressure of a solution obtained by mixing 100 cm^(3) of 1.5% solution of urea (mol. Mass=60) and 100 cm^(3) of 3.42% solution by cane sugar (mol. Mass = 342) at 20^(@)C . (R=0.082 litre atm/deg/mole)

Calculate the percentage composition of a solution obtained by mixing 200 g of a 20% and 300 g of a 30% solution by weight.

Osmotic pressure of solution containing 0.6 g urea and 3.42 g sugar in 100 ml at 27^@C