Home
Class 12
CHEMISTRY
Calculate the freezing point of an aqueo...

Calculate the freezing point of an aqueous solution having mole fraction of water `0.8`. Latent heat of fusion of ice is `1436.3 cal mol^(-1)`.

Text Solution

Verified by Experts

The correct Answer is:
`-25.97^(@)C` ;
Promotional Banner

Topper's Solved these Questions

  • DILUTE SOLUTION AND COLLIGATIVE PROPERTIES

    P BAHADUR|Exercise Exercise 3B Objectice Problems|1 Videos

  • CHEMICAL KINETICS

    P BAHADUR|Exercise Exercise 9|13 Videos

  • ELECTROCHEMISTRY

    P BAHADUR|Exercise Exercise (9) ADVANCED NUMERICAL PROBLEMS|36 Videos

Similar Questions

Explore conceptually related problems

Calculate the freezing point of an aqueous solution having mole fraction of water 0.8 . Latent heat of fusion of ice is 1436. "cal mol"^(-1) ?

Calculate the freezing point of a solution of a non-volatile solute in a unknown solvent of molar mass 30g//"mole" having mole fraction of solvent equal to 0.8 . Given that latent heat of fusion of solid solvent =2.7 "kcal mol"^(-1) , freezing point of solvent =27^(@)C and R=2 "cl mol"^(-1)K^(-1) .

Calculate the amount of heat required to convert5g of ice of 0^(@)C into water at 0^(@)C . ( Specific latent heat of fusion of ice 80 cal //g )

The entropy change in melting 1g of ice at 0^@C . (Latent heat of ice is 80 cal g^(-1) )

Calculate the entropy change (DeltaS) when 1 mol of ice at 0^(@)C is converted into water at 0^(@)C . Heat of fusion of ice at 0^(@)C is 1436 cal per mol.

If mole fraction of sodium chloride in sodium chloride aqueous solution is 0.35, then mole fraction of water in the solution is