Calculate the number of molecules in `2 xx 10^(-6)m^(3)` of a perfect gas at `27^(@) C` and at a pressure of 0.01 mm of mercury. Mean KE of a molecules at `27^(@) C = 4xx10^(-11) J and g = 9.8 m//s^(2)`.

Explanation

To calculate the number of molecules in a given volume of a perfect gas at a specific temperature and pressure, we can follow these steps:

### Step 1: Write down the given values
- Volume (V) = \(2 \times 10^{-6} \, m^3\)
- Temperature (T) = \(27^\circ C = 300 \, K\)
- Pressure (P) = \(0.01 \, mm \, Hg\)

### Step 2: Convert pressure from mm of mercury to Pascals
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