Two perfect gases at absolute temperature `T_(1) and T_(2)` are mixed. There is no loss of energy. The masses of the molecules are `m_(1) and m_(2)`. The number of molecules in the gases are `n_(1) and n_(2)`. The temperature of the mixture is

Explanation

Before mixing, kinetic energy of all the molecules of two gases `= 3/2 kn_(1)T_(1)+3/2 kn_(2) T_(2)`
If T is temperature of the mixuture , the average Ke of all molecules of two gases `= 3/2 k(n_(1)+n_(2))T = 32 k(n_(1)T_(1)+n_(2)T_(2))`
`T=(n_(1)T_(1)+n_(2)T_(2))/(n_(1)+n_(2))`.