Kinetic energy of oxygen molecule at `0^(@) C` is `9.4 xx 10^(-21) J`. Calculate Avogadro's number, when `R = 8.31 J "mole"^(-1) K^(-1)`.

Explanation

Here, `T= 0^(@) = 0+273 = 273 K`
K.E of `o_(2)` molecule = ` 9.4 xx 10^(-21)J`
Let N be the Avogadro's number
As K.E of an oxygen molecule = `5.2 R/N T`
`:. 9.4 xx 10^(-21) = ( 5xx 8.31 xx 273)/(2 xx 9.4 xx 10^(-21)) = 6.033 xx 10^(23)`.