The specific heat of argon at constant valume is `0.075 kcal kg^(-1) K^(-1)`. Calculate its atomic weight. `Take R = 2 cal mol^(-1) K^(-1)`.

Explanation

Argon is monoatomic gas with
`n=3`
`:. C_(upsilon) = 3/2 R = 3/2 xx 2 = 3 cal. Mol^(-1) K^(-1)`
We are given , `c= 0.075 kcal kg^(-1) K^(-1)`
`:. M=(C_(upsilon))/(c) = (3)/(0.075) = 40`
this is the atomic weight of argon.