One mole of a monoatomic gas is mixed with three moles of a diatomic gas. What is the molecular specific heat of mixture at constant volume? `R=8.31 J mol^(-1) K^(-1)`.

Explanation

To find the molecular specific heat of a mixture of one mole of a monoatomic gas and three moles of a diatomic gas at constant volume, we can follow these steps:

### Step 1: Identify the specific heat capacities of the gases
- For a monoatomic gas, the specific heat at constant volume \( C_{v1} \) is given by:
\[ C_{v1} = \frac{3}{2} R \]
- For a diatomic gas, the specific heat at constant volume \( C_{v2} \) is given by:
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