If one mole of a monatomic gas `(gamma=5/3)` is mixed with one mole of a diatomic gas `(gamma=7/5),` the value of gamma for mixture is

Explanation

As, ` gamma = (C_p)/(C_(upsilon)) =(C_(upsilon)+R)/(C_(upsilon)) = 1+(R)/(C_(upsilon))`
`:. C_(upsilon) = (R)/(gamma - 1)`
For monoatomic gas, `C(upsilon)= R/(5//3 - 1) = (3R)/(2)`
For diatomic gas, `C_(upsilon)^(') = R/(7//5 -1) =(5R)/(2)`
`C_(upsilon) (mixture) = (1 xx C_(upsilon) + 1 xx C_(upsilon)^('))/(1+1)`
`((3R)/(2)+(5R)/(2))/(2) = 2R`
`gamma (mixture) = 1+ (R)/(C_(upsilon)_(mix))=1+(R)/(2R) = 1.5`.