Estimate the mean free path for a water molecule in water vapour at 373 K. Given diameter of water molecule `= 2 Å` and number density of water molecule (at NTP) `= 2.7 xx 10^(25) m^(-3)`. Compare it with interatomic distance for water `= 40 Å`.

Explanation

To estimate the mean free path for a water molecule in water vapor at 373 K, we can follow these steps:

### Step 1: Convert the diameter of the water molecule to meters
The diameter of the water molecule is given as 2 Å (angstroms). We need to convert this to meters:
\[ D = 2 \, \text{Å} = 2 \times 10^{-10} \, \text{m} \]

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