Two perfect gases at absolute temperature `T_(1) and T_(2)` are mixed. There is no loss of energy. The masses of the molecules are `m_(1) and m_(2)`. The number of molecules in the gases are `n_(1) and n_(2)`. The temperature of the mixture is

Explanation

According to kinetic theory, the average K.E. Per molecule of a gas = `3/2 k_(B)T`
Before mixing, the average K.E. Of both the gases
`=3/2 k_(B) (n_(1)+n_(2)) T = 3/2 k_(B) n_(1)T_(1) + 3/2 k_(B)n_(2)T_(2)`
or `T=(n_(1)T_(1)+n_(2)T_(2))/((n_(1)+n_(2)))`.