Two simple harmonic are represented by the equation `y_(1)=0.1 sin (100pi+(pi)/3) and y_(2)=0.1 cos pit`.
The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is.

Explanation

At time `t=0`,
Velocity of particle 1 is
`v_(1)=(dy_(1))/(dt)=0.1cos(100pit+pi//3)xx100pi`
`=10picos(100pit+pi//3)`
Velocity of particle 2 is
`v_(2)=(dy_(2))/(dt)=0.1(-sinpit)pi=-0.1pisinpit`
`=0.1pi[cos(pit+pi//2)]`
At time `t=0`,
Phase of velocity of particle 1,
`phi_(1)=(100pixx0+pi//3)=(pi//3)`
Phase of velocity of particle 2,
`phi_(2)=(100pixx0+pi//3)=(pi//2)`
Phase differecne of velocity of particle 1 w.r.t. velocity of particle 2 at time `t=0`
`=phi_(1)-phi_(2)=(pi//3)-(pi//2)=-pi//6`