The bob of simple pendulum executes SHM in water with a period T, while the period of oscillation of the bob is `T_(0)` in air. Neglecting frictional force of water and given that the density of the bob is `(4000)/(3)kgm^(-3)` , find the ration between T and `T_(0)`.

Explanation

To find the ratio between the periods of oscillation of a simple pendulum bob in water (T) and in air (T₀), we can follow these steps:

### Step 1: Write the formula for the period of a simple pendulum in air
The period of a simple pendulum in air is given by the formula:
\[ T_0 = 2\pi \sqrt{\frac{L}{g}} \]
where \(L\) is the length of the pendulum and \(g\) is the acceleration due to gravity.
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