A simple pendulum is suspnded from the ceilignof a car accelerating uniformly on a horizontal road.If the acceleration is `a_0` and the length of the pendulum is l, find the time period of small oscillations about the mean position.

Explanation

In this problem, the pendulum has two acceleratios, a horizontal acceleration, `a_(x)=a` and a vertical downward acceleration, `a_(y)=g`. So, the resultant acceleration, `a=sqrt(ax^(2)+ay^(2))=sqrt(a^(2)+g^(2))`
So, the time period of oscillation of this simple pendulum is , `T=2pisqrt((l)/((a^(2)+g^(2))^(1//2)))`