The total magnification produced by a compound microscope is `20`. The magnification produced by the eye piece is `5`. The microscope is focussed on a certain object. The distance between the objective and eye piece is observed to be `14 cm`. If least distance of distinct vision is `20 cm`, calculate the focal length of objective and eye piece.

Explanation

To solve the problem step by step, we will use the formulas related to magnification and the properties of a compound microscope.

### Given:
- Total magnification (M) = 20
- Magnification by the eyepiece (ME) = 5
- Distance between the objective and eyepiece (L) = 14 cm
- Least distance of distinct vision (D) = 20 cm

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