The focal lengths of the objective and eye piece of a compound microscope are `4 cm and 6 cm` respectively. If an object is placed at a distance of `6 cm` from the objective, calculate the magnification produced by the microscope. Take distance of distinct vision `= 25 cm`.

Explanation

To solve the problem of calculating the magnification produced by a compound microscope, we will follow these steps:

### Step 1: Identify the given values
- Focal length of the objective lens, \( f_o = 4 \, \text{cm} \)
- Focal length of the eyepiece lens, \( f_e = 6 \, \text{cm} \)
- Object distance from the objective lens, \( u_o = -6 \, \text{cm} \) (the negative sign indicates that the object is on the same side as the incoming light)
- Distance of distinct vision, \( D = 25 \, \text{cm} \)

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