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In an astronomical telescope, focal leng...

In an astronomical telescope, focal length of objective lens is `75 cm` and that of eye piece is `5 cm` . Calculate the magnifying power and the distance between the two lenses, when final image of distant object is seen at a distance of `25 cm` from the eye.

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To solve the problem step by step, we will calculate the magnifying power of the astronomical telescope and the distance between the two lenses. ### Step 1: Calculate the Magnifying Power (M) The formula for the magnifying power of an astronomical telescope is given by: \[ M = -\frac{F_O}{F_E} \left(1 + \frac{F_E}{D}\right) ...
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PRADEEP-RAY OPTICS-Solved Example(d)
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  6. You are given two converging lenses of focal lengths 1.25 cm and 5cm t...

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  7. A person uses + 1.5 D glasses to have normal vision from 25 cm onwards...

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  8. A compound microscope has an objective of focal length 1 cm and an eye...

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  9. The total magnification produced by a compound microscope is 20. The m...

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  10. The focal lengths of the objective and eye piece of a compound microsc...

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  11. An astronomical telescope consists of the thin lenses, 36 cm apart and...

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  12. A small telescope has an objective lens of focal length 150 cm and and...

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  13. The diameter of the moon is 3.5 xx 10^3 km and its distance from the e...

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  14. An astronomical telescope has a magnifying power of 10. In normal adju...

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  15. A telescope has an objective of focal length 50 cm and eye piece of fo...

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  16. In an astronomical telescope, focal length of objective lens is 75 cm ...

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  19. The separation between the eye piece of focal length 0.3 m and objecti...

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  20. A reflecting type telescope has a large concave spherical mirror of ra...

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