Calculate the speed of light in a medium whose critical angle is `45^@`.

Answer

`2.12 xx 10^8 m//s`

Explanation

Here, `v = ?, C = 45^@`
`mu = (1)/(sin C) = (1)/(sin 45^@) = sqrt(2)`
`v = (c )/(mu) = (3 xx 10^8 m//s)/(sqrt(2)) = 2.12 xx 10^8 m//s`.