Find the radius of curvature of convex surface of a plano convex lens, whose focal length is `0.3 m and mu = 1.5`.

Answer

`0.15 m`

Explanation

Here, `R_2 = ? F = 0.3, mu = 1.5`
For plane surface of lens, `R_1 = oo : R_2 = - R`
From lens formula : `(1)/(f) = (mu - 1) ((1)/(R_1) - (1)/(R_2))`
`(1)/(0.3) = (1.5 - 1) ((1)/(oo) + (1)/( R)) = (1)/(2 R)`
`R = 0.15 m`.