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A screen is placed 80 cm from an object....

A screen is placed `80 cm` from an object. The image of the object on the screen is formed by a convex lens at two different locations separated by `10 cm`. Calculate the focal length of the lens used.

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To solve the problem, we will use the displacement method for a convex lens. Here’s the step-by-step solution: ### Step 1: Identify the given values - Distance from the object to the screen (D) = 80 cm - Distance between the two image locations (d) = 10 cm ### Step 2: Use the formula for focal length According to the displacement method, the focal length (f) of the lens can be calculated using the formula: \[ f = \frac{D^2 - d^2}{4D} \] ### Step 3: Substitute the values into the formula Now, we will substitute the values of D and d into the formula: \[ f = \frac{(80 \, \text{cm})^2 - (10 \, \text{cm})^2}{4 \times 80 \, \text{cm}} \] ### Step 4: Calculate \(D^2\) and \(d^2\) Calculating \(D^2\) and \(d^2\): \[ D^2 = 80^2 = 6400 \, \text{cm}^2 \] \[ d^2 = 10^2 = 100 \, \text{cm}^2 \] ### Step 5: Substitute the squared values back into the formula Now substituting these values into the formula: \[ f = \frac{6400 \, \text{cm}^2 - 100 \, \text{cm}^2}{4 \times 80 \, \text{cm}} \] \[ f = \frac{6300 \, \text{cm}^2}{320 \, \text{cm}} \] ### Step 6: Perform the division Now, we will perform the division: \[ f = \frac{6300}{320} \approx 19.6875 \, \text{cm} \] ### Step 7: Round off the answer Rounding off to two decimal places, we get: \[ f \approx 19.69 \, \text{cm} \] ### Final Answer The focal length of the lens used is approximately \(19.69 \, \text{cm}\). ---

To solve the problem, we will use the displacement method for a convex lens. Here’s the step-by-step solution: ### Step 1: Identify the given values - Distance from the object to the screen (D) = 80 cm - Distance between the two image locations (d) = 10 cm ### Step 2: Use the formula for focal length According to the displacement method, the focal length (f) of the lens can be calculated using the formula: ...
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PRADEEP-RAY OPTICS-Problem For Practice(b)
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  2. An object is placed at a distance of 1.5 m from a screen and a convex ...

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  3. A screen is placed 80 cm from an object. The image of the object on th...

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  4. A convergent beam of light passes through a diverging lens of focal le...

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  5. The image obtained with a convex lens is erect and its length is 4 tim...

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  6. An illuminated object and a screen are placed 90 cm apart. What is the...

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  7. A convex lens of focal length 25 cm is placed co-axially in contact wi...

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  8. The radius of curvature of the faces of a double convex lens are 10 cm...

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  9. A biconvex lens has focal length (2)/(3) times the radius of curvature...

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  10. An object is placed at a distance of 1.5 m from a screen and a convex ...

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  11. Find the focal length and power of a convex lens, which when placed in...

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  12. Find the focal length and nature of lens which should be placed in con...

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  13. Two lenses, one diverging of power 2 diopyre and the other converging ...

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  14. Two lenses of power + 10 D and - 5 D are placed in contact, (i) Calc...

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  15. A point object is placed 60 cm in front of a convex lens of focal leng...

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  16. A convex lens of focal length 15 cm, and a concave mirror of radius of...

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  17. Fig. shows a plane mirror M placed at a distance of 10 cm from a conca...

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  18. Monochramatic light is incident on the pLane interface AB between two ...

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  19. The image of a needle placed 45 cm from a lens is formed on a screen p...

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  20. A biconvex thin lens is prepared from glass (mu=1.5), the two bounding...

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