`- 40^(@)F ` को सेल्सियस में बदलिए ।

Explanation

`(F-32)/( 9) =( C )/( 5) `
` C = ( 5)/( 9) ( -40- 32) `
`= ( 5)/(9) (-72) = 5 xx(-8) `
`= - 40^(@)C `