The mass of the earth is `6.0 xx 10^(24) kg` and its radius is `6.4 xx 10^(6) m`. How much work will be done in taking a `10 kg` body from the surface of the Earth to infinity ? What will be the gravitational potential energy of the body on the Earth's surafce ?
`G = 6.67 xx 10^(-11) Nm^(2) kg^(-2)`.

Options

A. `(g)/( R)`
B. `( R)/(g)`
C. gR
D. `(g)/(R^(2)`

Answer

C

Explanation

The work done in shifting the body from the surface of the earth to infinity
= |Gravitational potential at the surface of the earth|
`=(GM)/(R )=((GM)/(R^(2)))R=gR`