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When light of wavelength lambda is incid...

When light of wavelength `lambda` is incident on photosensitive surface, the stopping potential is V. When light of wavelength `3lambda` is incident on same surface, the stopping potential is `V/6`Thereshould wave length for the surface is

A

`2lamda`

B

`3lamda`

C

`4 lamda`

D

`5lamda`

Text Solution

Verified by Experts

The correct Answer is:
D
`W_(0)=(hc)/(lamda)-eV_(s)`
`W_(0)=(hc)/(lamda_(1))-eV_(S_(1))=(hc)/(lamda_(2))-eV_(S_(2))`
`:.(hc)/(lamda)-eV=(hc)/(3lamda)-(eV)/(6)`
`(hc)/(lamda)-(hc)/(3lamda)=eV-(eV)/(6)`
`(hc)/(lamda)(1-(1)/(3))=(5eV)/(6)`
`(hc)/(lamda)((3-1)/(3))=(5eV)/(6)`
`(hc)/(lamda)=(5eV)/(6)xx(3)/(2)=(5eV)/(4):.eV=(4hc)/(5lamda)`
`:.W_(0)=(hc)/(lamda)-eV_(S_(1))`
`W_(0)=(hc)/(lamda)-(4hc)/(5lamda)`
`(hc)/(lamda_(0))=hc((1)/(lamda)-(4)/(5lamda))`
`(1)/(lamda_(0))=(5lamda-4lamda)/(5lamda^(2))`
`(1)/(lamda_(0))=(lamda)/(5lamda^(2))`
`(1)/(lamda_(0))=(1)/(5lamda)`
`:.lamda_(0)=5lamda`
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