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In the electrochemical reaction, 2Fe^(3+...

In the electrochemical reaction, `2Fe^(3+)+Zn rarr Zn^(2+) + 2Fe^(2+)` increasing the concentration of `Fe^(2+)`:

A

increasing cell emf

B

increasing the current flow

C

decreases the cell emf

D

alters the pH of the solution .

Text Solution

Verified by Experts

The correct Answer is:
C
`E_("cell") = E_("cell")^(@) - (RT)/(nF) "ln" ([Fe^(2+)]^(2))/([Fe^(3+)]^(2))` .
Increasing `[Fe^(2+)]` decreases `E_("cell")` .
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