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E^(@) for Fe//Fe^(2+) is +0.44 V and E^(...

`E^(@)` for `Fe//Fe^(2+)` is `+0.44 V` and `E^(@)` for `Cu//Cu^(2+)` is `-0.32 V`. Then, in the cell,

A

Cu oxidises `Fe^(2+)` ion

B

`Cu^(2+)` oxidises iron

C

Cu reduces `Fe^(2+)` ion

D

`Cu^(2+)` ion reduces Fe .

Text Solution

Verified by Experts

The correct Answer is:
B
EMF is +ve for `Fe + Cu^(2+) to Fe^(2+) + Cu`.
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