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For an electrolyte solution of 0.05 mol...

For an electrolyte solution of `0.05 mol L^(-1)` , the conductivity has been found to be `0.0110S cm^(-1)`. The molar conductivity is

A

`0.055 cm^(2) mol^(-1)`

B

`550 S cm^(2) mol^(-1)`

C

`0.22 S cm^(2) mol^(-1)`

D

`220 S cm^(2) mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`Lambda_(m) = k xx (1000)/("Molarity") = (0.11 xx 1000)/(0.05)`
`220 S cm^(2) mol^(-1)` .
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