0.1 M solution of an electrolyte `A^(+)B^(-)` placed in a conductivity cell wilth electrodes 4 cm apart and each with area of cross-section equal to 2 sq cm was found to have a resistance of `200 Omega`. The molar conductivity of the solution will be

Options

A. `25 Omega^(-1) cm^(2)`
B. `100 Omega^(-1) cm^(2)`
C. `0.25 Omega^(-1) cm^(2)`
D. `400 Omega^(-1) cm^(2)`

Answer

B

Explanation

`k = (1)/(R) xx (l)/(a) = (1)/(200) xx (4)/(2) = (1)/(100) Omega^(-1) cm^(-1)`,
`Lambda = k xx (1000)/("Molarity") = (1)/(100) xx (1000)/(0.1)`
`= 100 Omega^(-1) cm^(2)` .