A certain quantity of electricity is passed through an aqueous solution of `AgNO_(3)` and cupric salt solution connected in series . The amount of Ag deposited is 1.08 g. then the amount of copper deposited is (At. Mass Cu = 63.5 , Ag = 108) .

Options

A. 0.6454 g
B. 6.354 g
C. 0.3177 g
D. 3.177 g

Answer

C

Explanation

`("Wt. of Cu")/("Wt. of Ag") = ("Eq. of mass of Cu")/("Eq. mass of Ag")`
`("Wt. of Cu")/(1.08) = (63.5//2)/(108)`
or Wt. of Cu = `0.3177` g