Two electrolytic cells, one containing acidified ferrous sulphate and another acidified ferric chloride, are in series. The ratio of masses of Iron deposited at the cathode in the two cells will be

Options

A. `3 : 1`
B. `2 : 1`
C. `1 : 1`
D. `3 : 2`

Answer

D

Explanation

Eq. of mass of `Fe^(2+) ` = At.mass/2 = 56/2 .
Eq. mass of `Fe^(3+)` = At.mass /3 = 56/3 .
Weights deposited are in the ratio of their equivalents .
`therefore` Ratio of wts.deposited is
`Fe^(2+) : Fe^(3+) = (56)/(2) : (56)/(3) = (1)/(2): (1)/(3) = 3 : 2`