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A certain current liberated 0.504 g of h...

A certain current liberated 0.504 g of hydrogen in 2 hours. How many gram of copper can be liberated by the same current flowing for the same time in `CuSO_(4)` solution ?

A

`12.7`

B

`16`

C

`31.8`

D

`63.5`

Text Solution

Verified by Experts

The correct Answer is:
B
Eq. of `H_(2)` = Eq. of Cu
`therefore (0.504)/(1) = (w)/(63.5 //2)`
`therefore w_(Cu) = 16g`
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