On passing a current of 1.0 ampere for 16 min and 5 sec through one litre solution of `CuCl_(2)` , all copper of the solution of `CuCl_(2)` solution was (Molar mass of Cu = 63.5 , Faraday constant = `96500 C mol^(-1)`).

Options

A. 0.07 M
B. 0.2 M
C. 0.005 M
D. 0.02 M

Answer

C

Explanation

`Q = 1 xx 965 = 965` C
`Cu^(2+) + 2e^(-) to Cu`,
`2 xx 96500` C decompose `CuCl_(2) = 1 ` mole
`therefore` 965 C decompose `CuCl_(2) = (1 xx 965)/(2 xx 96500) =(1)/(200)` mole
This was present in one litre of `CuCl_(2)` solution .
Hence , strength = 0.005 M.