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When the electrolytis of silver sulphate...

When the electrolytis of silver sulphate was carried out by Pt electrodes. 1-6 g oxygen was liberated at the anode, the amount of silver deposited at cathode will be

A

0 g

B

0.108 g

C

0.108 g

D

1.08 g

Text Solution

Verified by Experts

The correct Answer is:
A
`Ag^(+) + e^(-) to Ag` i.e., 1 F deposits Ag = 108 g
`therefore` 0.01 F will deposit Ag = 1.08 g .
Hence , Ag content left = 0
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