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The volume of H(2) gas at NTP obtained b...

The volume of `H_(2)` gas at NTP obtained by passing 4 amperes through acidified `H_(2)O` for 30 minutes is

A

`0.0836` litre

B

`0.1672 ` litre

C

`0.0432 ` litre

D

`0.836` litre

Text Solution

Verified by Experts

The correct Answer is:
A
Faraday's `I^(st)` law
`W = (E.i.t)/(96500) = (1 xx 0 .4 xx 30 xx 60)/(96500) = 7.46 xx 10^(-3)` g
`V = (W xx 22.4 L)/("Molar mass") = (7. 46 xx 10^(-3) xx 22.4)/(2)= 0.0836` litre
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